Question

first find the foci then find the vertices in the quadratic

Answer 1

@ganeshie8 I tried to solve this one using the hyperbola table from the previous question but I couldn't, because the sign here is +ve
please let me know if you can help.

Answer 2

this is an ellipse

Answer 3

This is the equation of an ellipse (not hyperbola).
\[\frac{ x^2 }{ a^2} + \frac{ y^2 }{ b^2} = 1\]
Compare the given equation to the standard form and identify a, b, the center of the ellipse, etc.

Answer 4

ok so thats why

Answer 5

this is the table from the previous question

Answer 6

basically u have 4 kinds of conic sections :
1) circle
2) parabola
3) ellipse
4) hyperbola

Answer 7

ok @ganeshie8 and @ranga one minute I'm solving it and I'll post my answer

Answer 8

got it so four conic shapes

Answer 9

they're all related, but u need to use the corresponding tables and im sure u wil see how they're related later...

Answer 10

for now, go ahead and use the table..

Answer 11

yes I'm using it now

Answer 12

maybe figure out "a, b, c" values first

Answer 13

to find out vertices, just "a" value is sufficient :

vertices = \((\pm a, 0)\)

Answer 14

foci (0,7) and (0,-7)

Answer 15

nope

Answer 16

a = 10
b ~ 7.14

right ?

Answer 17

oh sorry his one is HORIZONTAL

Answer 18

Yes ! since a > b, its a horizontal ellipse

Answer 19

this*

Answer 20

so the foci will be (7,0) (-7,0)