Find the solutions to the system
y=x^2+5x+6
y=4x+12

Question

Find the solutions to the system 
y=x^2+5x+6
y=4x+12

anonymous · Answer

$$solve~ x^2+5x+6=4x+12~and~find~the~values~of~x $$
and then corresponding values of y.

ranga · Answer

You are basically substituting the y from the second equation into the first, eliminating y.
Solve for x.  Bring all the terms on the right in surjithayer's post to the left, simplify, and solve the quadratic equation.

anonymous · Answer

Solving this system means finding the x -coordinates of the 2 intersections of  a line and a parabola. There should be 2 points, meaning two values of x.
x^2 + 5x + 6 = 4x + 12
x^2 + x - 6 = 0
D = b^2 - 4ac = 1 + 24 = 25 -> VD = 5
x1 = -1/2 + 5/2 = 2, and x2 = -1/2 - 5/2 = -3.

ranga · Answer

Solving the quadratic equation by factoring will be a lot easier in this case.

yanasidlinskiy · Answer

Set the equations equal to each other.

anonymous · Answer

y=x^2+5x+6
y=4x+12
y=y right? so
x^2+5x+6=4x+12
x^2+x-7=0
use quadratic formula and you will have your roots/x coords/x intercepts