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please find the x-intercept
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To find the x intercept of an equation, find the value where y = 0
ok so i plugin y=0 first
ya and solve from there
maybe use quadratic formula
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Yes, you need to plug it into the quadratic formula to solve for y = 0
remember FOIL
\(\large x = \frac{-b \pm \sqrt{b^2 - 4\times a\times c}}{2a}\)
^thats for solving \(ax^2 + bx + c = 0\)
figure out a, b, c values and plugin
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this formula is easier I think
I will use it now and solve
-b +/- (sqrt)b^2 - 4ac / 2a -15 +/- (sqrt) 225 + 80 / 2(10) -15 +/- (sqrt) 265 / 20 The answer is A.
\[\frac{ -15+- \sqrt{305} }{ 20 }\]
yes so it is A
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I meant 305 not 265.
thanks @ganeshie8 , @Abbles ,@elementwielder thanks for helping :)
yes got it A (305)
:) anytime
No problem ;)
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