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Mathematics 21 Online
OpenStudy (anonymous):

please find the x-intercept

OpenStudy (anonymous):

OpenStudy (abbles):

To find the x intercept of an equation, find the value where y = 0

OpenStudy (anonymous):

ok so i plugin y=0 first

OpenStudy (anonymous):

ya and solve from there

ganeshie8 (ganeshie8):

maybe use quadratic formula

OpenStudy (abbles):

Yes, you need to plug it into the quadratic formula to solve for y = 0

OpenStudy (anonymous):

remember FOIL

ganeshie8 (ganeshie8):

\(\large x = \frac{-b \pm \sqrt{b^2 - 4\times a\times c}}{2a}\)

ganeshie8 (ganeshie8):

^thats for solving \(ax^2 + bx + c = 0\)

ganeshie8 (ganeshie8):

figure out a, b, c values and plugin

OpenStudy (anonymous):

this formula is easier I think

OpenStudy (anonymous):

I will use it now and solve

OpenStudy (abbles):

-b +/- (sqrt)b^2 - 4ac / 2a -15 +/- (sqrt) 225 + 80 / 2(10) -15 +/- (sqrt) 265 / 20 The answer is A.

OpenStudy (anonymous):

\[\frac{ -15+- \sqrt{305} }{ 20 }\]

OpenStudy (anonymous):

yes so it is A

OpenStudy (abbles):

I meant 305 not 265.

OpenStudy (anonymous):

thanks @ganeshie8 , @Abbles ,@elementwielder thanks for helping :)

OpenStudy (anonymous):

yes got it A (305)

OpenStudy (anonymous):

:) anytime

OpenStudy (abbles):

No problem ;)

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