Write the equation of the line that is parallel to the line 3x - y = -3 and passes through the point (4, -2).
You need to use point-slope form, because you have one point already and the slope (since it's parallel) will be the same as the original equation. Put that into y = mx + b (y-intercept form) to find the slope, or you could just look at it and tell.
so...
im sorry im not good at this
No that's fine, this site is here to help :) So first you need to get the original equation into y-intercept form by isolating the y. 3x - y = -3 -y = -3x - 3 y = 3x - 3 We can now see that 3 is the slope of this line and the slope we will use in the point-slope equation. Point-slope formula is: y - y1 = m(x - x1). Can you plug in the slope 3 and the point (4, -2) into that? y1 is your first y value (-2) and x1 is the x coordinate (4). M is the slope.
yeah let me try
-2 - y^1 = 3(4 - x^1)
-2 - 4 = 3(4 - (-2)) is that better?
Almost! You were close. y - y1 = m(x - x1) y + 2 = 3(x - 4) Now we just need to solve this. y + 2 = 2x - 12 y = 2x -14 What form do you need the answer in? y + 2 = 3(x - 4) Would be an acceptable answer if you just need it in point-slope form. Otherwise, I'd say go with the y-intercept form, giving you y = 2x -14 as the answer. :) Do you understand where I went with this?
it has to be one of these y = -one thirdx - 6 y = -one thirdx - 14 y = 3x - 6 y = 3x - 14
Oh I made a small typo :P sorry. Do you see where I had 3(x - 4) and I used the distributive property? I put 2x instead of 3x. The answer would be y = 3x - 14 instead of y = 2x - 14. Sorry for the confusion!
thanks a lot and heres a medal
Anything and thanks :) right back at ya
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