A rational expression has been simplified below.
(x+4)(x-2)/9(x-2)= x+4/9
For what values of x are the two expressions equal?

Question

A rational expression has been simplified below.
(x+4)(x-2)/9(x-2)= x+4/9
For what values of x are the two expressions equal?

anonymous · Answer

$$\frac{ (x+4)(x-2) }{9(x-2) }=x+\frac {4}{9}$$
The first thing to do here is simplify both sides. X=4/9 is simplified, but you can simplify the other side by canceling out the (x-2) in the numberator and denominator.
$$\frac {x+4}{9}=x+\frac{4}{9}$$
Now just solve for x.
$$9\times(\frac {x+4}{9})= 9 \times (x+\frac{4}{9})$$$$x+4=9x+4$$$$8x=0$$
$$x=0$$
So when x=0, the two expressions are equal.

anonymous · Answer

Please verify the problem. The expression should be 
(x + 4)(x - 2)/9(x - 2)= (x + 4)/9. After simplification by (x - 2) , the remainder is (x + 4)/9.
When x = -4, both sides equal to zero
When x = 0 , both sides equal to 4/9