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Chemistry 7 Online
OpenStudy (amtran_bus):

Where am I messing up??

OpenStudy (amtran_bus):

From the solubility data given, calculate the solubility products for the following compounds: (a) SrF2, 7.3 x 10-2 g/L (b) Ag3PO4, 6.7 x 10-3 g/L

OpenStudy (amtran_bus):

For part a, cant you say7.3x10^-2 =4s^3??

OpenStudy (amtran_bus):

@aaronq

OpenStudy (aaronq):

you converted to the masses to moles?

OpenStudy (amtran_bus):

By dividing by the molar mass?

OpenStudy (aaronq):

yeah

OpenStudy (amtran_bus):

7.3x10^-2/125.62=.000581 Now divide by 4 and take cubed root of ans?

OpenStudy (aaronq):

no, i think they're asking you for the solubility product constant. so Ksp=\(4(0.000581)^3\)

OpenStudy (amtran_bus):

OHH! So solubility =s and molar solubility =Ksp?

OpenStudy (aaronq):

yeaah

OpenStudy (amtran_bus):

Thanks! Never ran into a problem like that before.

OpenStudy (aaronq):

no problem! i think thats what they're asking for, you should double check though

OpenStudy (amtran_bus):

Ok. I know usually you make the ICE table to determine the factor (like 4s^3).

OpenStudy (aaronq):

yeah, you would, but you can always assume it's that when you have a \(XY_2\) compound

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