what is cos 2pi/3?
a. -3sqrt/2
b. sqrt 3/2
c. -1/2
d. 1/2 ( i think its b or c)
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OpenStudy (kc_kennylau):
Convert it into degrees if that helps; or draw a unit circle if that helps
OpenStudy (kc_kennylau):
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OpenStudy (anonymous):
120'
OpenStudy (kc_kennylau):
What's its supplementary angle?
OpenStudy (kc_kennylau):
Formula: \(\cos(180^\circ-\theta)=-\cos\theta\)
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OpenStudy (anonymous):
60?
OpenStudy (kc_kennylau):
Or you can use \(\cos(90^\circ+\theta)=-\sin\theta\) which is more standard
OpenStudy (kc_kennylau):
Choose one of the formulas that I gave you
OpenStudy (anonymous):
the first one.
OpenStudy (kc_kennylau):
Then use it
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OpenStudy (anonymous):
but what do i use in place of the theta?
OpenStudy (kc_kennylau):
60`
OpenStudy (anonymous):
in both of them?
OpenStudy (kc_kennylau):
Both of what? You've chosen a formula already
OpenStudy (anonymous):
yes. but do i put 60 in both of the thetas?
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OpenStudy (kc_kennylau):
\[\cos120^\circ=\cos(180^\circ-60^\circ)=\cdots\]
OpenStudy (kc_kennylau):
P.S. Schools prefer the second formula
OpenStudy (kc_kennylau):
So I'll use the first formula and you'll try to use the second formula.
Using the first formula: \(\cos120^\circ=\cos(180^\circ-60^\circ)=-\cos60^\circ=-0.5\)
OpenStudy (anonymous):
-1/2?
OpenStudy (kc_kennylau):
Yes
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OpenStudy (kc_kennylau):
Standard method: \(\displaystyle\cos\frac{2\pi}3=\cos\left(\frac\pi2+\frac\pi6\right)=-\sin\left(\frac\pi6\right)=-\frac12\)