Question

If cosθ= -15/13 and sin θ< 0, what is tan θ??

a.12/5
b. 13/5
c. -12/5
d. sqrt 194/5

Answer 1

Use \(\cos^2\theta+\sin^2\theta=1\) to find \(\sin\theta\) first

Answer 2

in the first theta i put -15/13? and the second i put (theta)<0?

Answer 3

\(\cos\theta\) is NOT \(\cos\) times \(\theta\)

Answer 4

\(\cos\theta\) is one entity; \(\sin\theta\) is one entity

Answer 5

i dont understand im sorry im trying

Answer 6

Treat \(\cos\theta\) as one thing instead of two things

Answer 7

And bear in mind the notation: \(\cos^2\theta=(\cos\theta)^2\)

Answer 8

So the formula would be \((\cos\theta)^2+(\sin\theta)^2=1\)

Answer 9

Substitute \(\cos\theta=-\dfrac{15}{13}\) inside to find the value of \(\sin\theta\)

Answer 10

i got no solution -.-

Answer 11

Oh, sorry, I forgot to check the validity

Answer 12

\(\cos\theta\) and \(\sin\theta\) must be between -1 and 1

Answer 13

So no solution

Answer 14

so noww what do i do to find tan(theta)

Answer 15

You can't; theta doesn't even exist

Answer 16

so then what would the answer be?
:0

Answer 17

13/5?

Answer 18

An answer doesn't exist

Answer 19

i found out it was 12/5 idk how

Answer 20

No it isn't; it doesn't even exist

Answer 21

Or did you mistype the question?

Answer 22

nope my school just dont make sence