Question

log base5 2+2 log base5 x=log base5 (3-x)

Answer 1

\[\log_{5}2+2\log_{5}x=\log_{5}(3-x) \]

Answer 2

You could use log_5(2) where we'll understand that you mean \(\log_52\)

Answer 3

Convert the left hand side into one thing first

Answer 4

Would they cancel out and I would be left with just x?

Answer 5

I don't exactly get what you mean by cancel out, but you'd need the log formulas for this:
\[\Large\log_na+\log_nb=\log_n(ab)\]\[\Large n\log_ma=\log_ma^n\]

Answer 6

Okay one sec lemme try to figure it out :)

Answer 7

okay :)

Answer 8

Kinda stuck :/

Answer 9

Using the second formula, \(\Large2\log_5x=?\)

Answer 10

\[\log_{5}x^2 \] ?

Answer 11

Yep

Answer 12

Oh my . I had that written down and I thought it was wrong -_-

Answer 13

Sorry I have to go now, use http://wolframalpha.com/ to check your answer

Answer 14

Okay thanks