Question

How do you rearrange this function for y in terms of x.... x=e^-7y +3 Thanks! :)

Answer 1

\(x=e^{-7y}+3\)
\(\large ?\)

Answer 2

@VintageTypewriter ?

Answer 3

Sorry...I was trying to do it :) like that

Answer 4

\(x-3=e^{-7y}\implies \log(x-3)=\log(e^{-7y})\implies \log(x-3)=-7y\\y=\frac{-\log(x-3)}{7}\)

Answer 5

\(\log(x)=\log_e(x) = \text{ln}(x)\)

Answer 6

oh!!! Thanks :) :) Makes so much sense now!

Answer 7

np

Answer 8

so...how would you find the domain? is x not defined when log (x-3) < or equal to 0

Answer 9

I mean when \[(x-3)\le0\]

Answer 10

\(x-3>0\)

Answer 11

you want the domain of the new function?

Answer 12

yeah

Answer 13

oh yes greater than...sorry....my mistake