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OpenStudy (anonymous):

Algebra Help :/

OpenStudy (anonymous):

1. To open these doors, you must match the number and type of solutions for the following two fuctions in standard form. f(x) = x2 + 6x – 16 g(x) = x2 +6x + 1 Match the following descriptions of the solutions to each of the functions above. Hint: they each have their own match. Two real irrationals solutions. Two real rationals solutions. After matching these functions, explain to Professor McMerlock how you know these functions meet each condition.

OpenStudy (anonymous):

2, “To pass by me you must tell me how to convert standard form into the general, vertex form... I have a test on it next week.” Explain how to convert f(x) into the general, vertex form of the equation. Use complete sentences"

OpenStudy (anonymous):

3. “Only the solutions of g(x) will lead you safely across.” Find the solutions of g(x). Show each step

OpenStudy (anonymous):

@iPwnBunnies do you know how to do this?

OpenStudy (ipwnbunnies):

For the first question, you want to find the discriminant for each function. That will tell you what kind of solutions each quadratic equation will have.

OpenStudy (ipwnbunnies):

http://www.mathwarehouse.com/quadratic/discriminant-in-quadratic-equation.php Check out the top half of this link explaining that.

OpenStudy (anonymous):

So #1 would be f(x)= 100 and g(x)= 32? @iPwnBunnies

OpenStudy (ipwnbunnies):

Are those the discriminant of both functions? Great, now what does that tell us about the solutions? There is a chart on the same link.

OpenStudy (anonymous):

They are two irrational solutions

OpenStudy (ipwnbunnies):

There are two irrational solutions for g(x), since the discriminant is positive and not a perfect square. How about f(x)?

OpenStudy (anonymous):

That would be rational, because 100 is a perfect square

OpenStudy (ipwnbunnies):

Good job man.

OpenStudy (anonymous):

Thanks :D, that was actually simple, they worded it oddly. For 2. is there a formula to convert f(x) to vertex form?

OpenStudy (ipwnbunnies):

Yes, but I'm not familiar with it, or it's because I can't remember lol.

OpenStudy (ipwnbunnies):

But for number 3, we can find the solutions to g(x) either by the quadratic formula, or if it's easy to factor, finding the zeroes using factors.

OpenStudy (anonymous):

Alright thank you, I'll tell you my answer

OpenStudy (ipwnbunnies):

Just a hint, g(x) isn't easy to factor, so we will have to use the quadratic formula.

OpenStudy (anonymous):

Yeah that's what I did and I got x= -.17 and -5.83 @iPwnBunnies

OpenStudy (ipwnbunnies):

That looks correct, good job.

OpenStudy (ipwnbunnies):

http://www.wolframalpha.com/input/?i=x%5E2+%2B+6x+%2B+1

OpenStudy (anonymous):

Thanks :D What's that link for? @iPwnBunnies

OpenStudy (anonymous):

Oh I see it, cool :o

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