Why couldn't you substitute 3M H2SO4 for concentrated HNO3

Question

aaronq · Answer

it depends on what you're doing, $H_2SO_4$ is diprotic, while $HNO_3$ is monoprotic. In other words, sulfuric acid contributes twice as many $H^+$ than nitric acid does.

anonymous · Answer

It's based on a lab about transforming copper

aaronq · Answer

to be honest idk what you're doing, so i can't tell you. Post more info if you want

anonymous · Answer

could i ask you another question i need help answering?

aaronq · Answer

sure

anonymous · Answer

Briefly explain whether the following procedural errors would result in either an incorrectly high or incorrectly low calculated percent Cu recovery for this experiment.
 
A) This solution was not basic when it was heated in part 3. ( in part 3 i convertedCu(OH)2 to CuO).
B) A slightly blue solution was decanted from Cu in part V. (in part 5 i reduced Cu(H20)6 ions with zink)
C) In part 5 the water in the beaker boiled away, exposing the evaporating dish to excess heat (same as above).

anonymous · Answer

Thank you!

anonymous · Answer

?

aaronq · Answer

I honestly don't know, I have to think about it but i have to go. Sorry. You should repost it as a new question and hopefully someone helps you. if not i'll see it later today and try help you out.

It would also help if you gave a more thorough background, like what you're measuring in terms of recovery and whatnot. good luck