Question

Help please

Answer 1

\[3\sqrt{5c}*7\sqrt{15c^2}\]

Answer 2

then
\[21\sqrt{75c^3}\]

Answer 3

are you solving for c? or simplifying?

Answer 4

then
\[21*5\sqrt{3c ^{3}}\]

Answer 5

simplifying

Answer 6

Now what am I suppose to do?

Answer 7

\(\large c^3 =c^2 c\)

Answer 8

so u can pull out a \(c\) put of squareroot ?

Answer 9

so then it would be
\[105c \sqrt{3c^2}\]

Answer 10

Like that?

Answer 11

not quite

Answer 12

\(\large 21*5\sqrt{3c^3}\)

\(\large 21*5\sqrt{3c^2c}\)

\(\large 21*5*c\sqrt{3c}\)

\(\large 105c\sqrt{3c}\)

Answer 13

when u pull out, c^2 becomes c

Answer 14

oh

Answer 15

and thats it right?

Answer 16

yes, \(\large \sqrt{x^2} = x\)

Answer 17

yup thats it

Answer 18

Thank you

Answer 19

yw