Question

Find the center, vertices, and foci of the ellipse with equation x^2/81+y^2/225=1
@agent0smith

Answer 1

Center is (0, 0)

foci will be (0, c) and (0, -c) where c^2 = b^2 - a^2

and b^2 = 225 and a^2 = 81

Answer 2

Center: (0, 0); Vertices: (0, -15), (0, 15); Foci: (0, -12), (0, 12)

Answer 3

Find the center, vertices, and foci of the ellipse with equation 2x2 + 8y2 = 16.

Answer 4

Divide everything by 16, then it's almost the same as above, but this one is horizontal, so

foci (c, 0) and (-c, 0) where c^2 = a^2 - b^2

Answer 5

(0,-sqrt 6) (0,sqr 6)

Answer 6

close but see above post

Answer 7

oh wait -sqt6,0 and sqrt6,0

Answer 8

no/?

Answer 9

Yes