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Differentiate F(x) = (log9 x)7
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You mean \(\log_9x\) or \(\log9x\)?
the first one
Some log formula: \(\Large\frac{\log_na}{\log_nb}=\log_ba\)
In this case you'd like to transform it to \(\Large\left(\dfrac{\ln x}{\ln 9}\right)^7\)
Chain rule?
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so the final answer would be (ln x/ln 9)^7?
No, this is only the question
I'm kinda lost right now but ok
\[\Large(\log_9x)^7=\Large\left(\dfrac{\ln x}{\ln 9}\right)^7\]
oh ok. i see now. thanks
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Continue using chain rule?
Benji - did you check my last answer (half-life)?
yes wolfman1728. i figured how to do it. thanks for the help you guys
Okay - and sorry for the interruption.
Treat \(\dfrac{\ln x}{\ln9}\) as one thing first, now differentiate it
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