Question

PLEASE HELP! Am I right? /:

-a^2 - 3b^3 + c^2 + 2b^3 - c^2
(-3)^2 - 3(2)^3 + (-3)^2 + 2(2)^3 - (-3)^2
-9 - 24 + -9 + 16 - -9
= -17

Answer choices:
a) -67
b) -17
c) -31
d) 1

I'm confused because I calculated line 2 in the calculator, and it came out as 1.

Answer 1

a stands for 3
b stands for 2
c stands for -3

Answer 2

-3^2 - 3(2^3) + (-3^2) + 2(2^3) - (-3^2)
9 - 3(8) + 9 + 2(8) - (9)
9 - 24 + 9 + 16 - 9
- 33 + 34
1

Answer 3

-a^2 - 3b^3 + c^2 + 2b^3 - c^2

Replace those values with the given A, B and C

\(\ \color{orange}{A}\rightarrow\color{orange}{3} \)

\(\ \color{blue}{B} \rightarrow \color{blue}{2}\)

\(\ \color{green}{C} \rightarrow \color{green}{-3}\)

\(\ \sf \Large -a^2 - 3b^3 + c^2 + 2b^3 - c^2 \Longrightarrow \color{orange}{3}^2 - 3\color{blue}{(2)}^3 + \color{green}{(-3)}^2 + 2\color{blue}{(2)}^3 - \color{green}{(-3)}^2\)

\(\ \sf \Large \color{orange}{3}^2 = \color{orange}{(9)} \)

\(\ \sf \Large -3\color{blue}{(2)}^3 = -3\color{blue}{(8)} = \color{blue}{(-24)} \)

\(\ \sf \Large + \color{green}{(-3)}^2 = \color{green}{(9)} \)

\(\ \sf \Large 2\color{blue}{(2)}^3 = 2\color{blue}{(8)} = \color{blue}{(16)} \)

\(\ \sf \Large -\color{green}{(-3)}^2 = -\color{green}{(9)} = \color{green}{(-9)}\)

\(\ \sf \Large \color{orange}{(9)} + \color{blue}{(-24)} + \color{green}{(9)} + \color{blue}{(16)} + \color{green}{(-9)} = 1 \)

Answer 4

U_U it cut off...

It was suppose to be -(-3)^2 = -(9) = - 9

Answer 5

@tHe_FiZiCx99 Isn't it supposed to be -9 tho? -3^2 = -9

Answer 6

Anything raised to a square is positive regardless of the signs because

-3^2 is the same thing as -3 * -3 = 9

2 negatives = positive
1 negative and 1 positive = negative
2 positive = positive

Answer 7

@tHe_FiZiCx99 Ok thanks! I don't know how I forgot that. :P

Answer 8

You're welcome :>