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5^(x+2)= 2^(3-x)
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What do you want to do with the problem? Factor Simplify Solve for x ??
Solve for X
Hit both sides with log.
\(\Huge\color{blue}{ \sf 5^{(x+2)}= 2^{(3-x)} }\) \(\Large\color{blue}{ \sf (x+2)Log5= (3-x)Log2 }\)
I logged both with the same log
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\(\Large\color{blue}{ \sf \frac{(x+2)}{(3-x)} = \frac{Log5}{Log2}=Log_25 }\)
Ok I understand the first two parts of your last post but not your final answer.
I am solving for X so does x = \[\log_{2} 5\]?
Nope
Don't divide
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Expand (x+2)Log5=(3−x)Log2
\[x\log5+2\log5=3\log2-x\log2\]
\[x(\log5+\log2)=3\log2-2\log5\]
\[x=\frac{3\log2-2\log5}{\log5+\log2}=\cdots\]
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