Choose the correct solution of the given system of equations. y + 2x = -1 3y - x = 4
Solutions a. (-1,1) b. (1,1) c. no solution d. none of the above
Is this the one where you can subtract them from each other? Or sub?
ya
Do you know how to solve the system of equations?
ya. sort of
for the most part
Okay, so solve it :-)
:( your no fun. :) lol
I always seem to end up with really long numbers like irrational decimals
I sub x with ) for the first equation and got -1, but i don't know if I'm doing it right lol
how'd u do it?
@whpalmer4 , is it b?
i think it might be b
wait
it could be a
:(
y+2(0)=-1 y+0=-1 (add 0 to both the 0 & the -1) 0 cancels out and you get y=-1
I think it might be A, but don't lean on me lol
You would subtract 0 from both sides In this 1 it doesnt really matter, but u would subtract
The answer is a
Good night
Yea, I meant subtract...Goodnight
\[y + 2x = -1\]\[3y - x = 4\] We can easily solve the first equation for \(y\), or the second equation for \(x\). Let's do the former: \[y + 2x = -1\]\[y = -1-2x\]Now substitute that into the other equation: \[3(-1-2x)-x = 4\]\[-3-6x-x = 4\]\[-7x=7\]\[x=-1\]Now put that in the substitution equation to find \(y\):\[y = -1-2(-1)\]\[y = -1+2\]\[y = 1\]So our solution is \((-1,1)\) Checking: \[1+2(-1) = -1\checkmark\]\[3(1)-(-1) = 4\checkmark\]
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