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1 = 2ln(900/900-x) Solve for x
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@Chineseboy15
Divide both sides by 2
ok
man do it
so 1/2 = ln(900/900-x) raise each side to e
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e^(1/2) = 900/(900-x)
900-x = 900/e^(1/2)
x = 900 - 900/e^91/2)
?
Congratulations :D
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answer in my book is Po = 900(1-e^(-6))
Can you give me the original question?
Time of extinction = 2ln(900=/900 - x) I used x instead of Po sorry. If time of extinction = 1 year find x (Po which is initial population.)
hmm...
maybe your book is wrong?
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