A 45.0 kg skater is skating at a speed of 12.0 m/s. The skater coasts to a speed of 6.00 m/s. How much kinetic energy has the skater lost?
\[\frac{ 1 }{ 2 }mv ^{2}\] is the formula for kinetic energy. m is 45 in this instance. v is the velocity of the skater. First calculate the skater with initial velocity, then with his final. Difference is the kinetic energy lost
im still lost
First you have to calculate the kinetic energy the skater has while he is skating at 12 m/s. Just put the numbers into the formula. V is the velocity which is 12 here. Then as he coasts to 6 m/s, you calculate the kinetic energy while at 6 m/s. The difference between what you find is how much kinetic energy is converted into other forms of energy. Which is your answer.
ok i think my answer is 2430joules
Yes it is
ok thanks
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