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Physics 8 Online
OpenStudy (anonymous):

A 45.0 kg skater is skating at a speed of 12.0 m/s. The skater coasts to a speed of 6.00 m/s. How much kinetic energy has the skater lost?

OpenStudy (anonymous):

\[\frac{ 1 }{ 2 }mv ^{2}\] is the formula for kinetic energy. m is 45 in this instance. v is the velocity of the skater. First calculate the skater with initial velocity, then with his final. Difference is the kinetic energy lost

OpenStudy (anonymous):

im still lost

OpenStudy (anonymous):

First you have to calculate the kinetic energy the skater has while he is skating at 12 m/s. Just put the numbers into the formula. V is the velocity which is 12 here. Then as he coasts to 6 m/s, you calculate the kinetic energy while at 6 m/s. The difference between what you find is how much kinetic energy is converted into other forms of energy. Which is your answer.

OpenStudy (anonymous):

ok i think my answer is 2430joules

OpenStudy (anonymous):

Yes it is

OpenStudy (anonymous):

ok thanks

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