Question

What number would you have to add to both sides to complete the square?



x2 + 12x = –6



A.
–36


B.
36


C.
144


D.
–144

I thinks it's c but I'm not sure

Answer 1

So to complete the square ...you take the coefficient of the 'x' ...divide it by 2....and then square the result...

so that coefficient is 12...

half of that is 6

6 square = 36 ....so we would add 36 to both sides of our equation

Answer 2

omg thank you soo much

Answer 3

Anytime :)

Answer 4

can you help with more?

Answer 5

@johnweldon1993

Answer 6

Of course :)

Answer 7

Solve by using the perfect squares method.



x2 + 16x + 64= 0



A.
–8


B.
–16


C.
16


D.
8


i think b

Answer 8

sorry i meant a

Answer 9

Alright so perfect squares method means... you can turn something like that into something like

(x + 8)^2

Why? because when you factor that out you get

(x + 8)(x + 8)
x^2 + 8x + 8x + 64
x^2 + 16x + 64

Well that is correct...so it looks like my hunch was correct....now what would make

(x + 8)^2 = 0?

Looks like if you add -8 to 8..you get 0 right? So -8 it is....you are correct :)

Answer 10

yay!

Solve. x2 – 5x + 6 = 0



A.


{3, –2}


B.


{2, 3}


C.


{–2, –3}


D.


{5, –1}



is it b

Answer 11

Indeed it is B

See you're a pro at these :)

Answer 12

Solve.

2x2 + x – 1 = 9

i think it is 2, -5/2

Answer 13

You would be correct!

Answer 14

yay!



2x2 + 8x = 0



A.


{0, 4}


B.


(0,-1/4

C.


{0, –4}


D.


{3, 5}

Answer 15

And your guess?

Answer 16

c

Answer 17

Correct :)

Answer 18

okay last one i swear


Use the discriminant to determine the number and type of solutions the equation has.



x2 + 6x + 12 = 0



A.
two rational solutions


B.
two irrational solutions


C.
no real solution


D.
one real solution

is it b?

Answer 19

Thank you soo much I really appreciate you helping me @johnweldon1993

Answer 20

Not quite...irrational just means a decimal number that will go on forever

But the discriminant is

\[\large b^2 - 4ac\]
\[\large 6^2 - 4(1)(12)\]
\[\large 36- 48 = -12\]

When the discriminate comes out as a negative...it shows that you have no REAL solutions to the equation...you instead have a complex solution...so this would be C

Answer 21

And yes of course @sierraleone17 :)

Answer 22

thank you thank you thank you

Answer 23

Anytime :)