SOMEONE PLEASE HELP THIS NEEDS TO BE FINISHED TODAY! A(t)=P(1+r/n)^nt A(t)=39,145(1+.03/12)^12t Being a smart financial planner, you want to figure out how many months it will be until your principal is paid down to $10,000.00. Solve for t and show all of your work. Note that t will be negative because the number of months will decrease the principal. Lastly, you decide to keep track of your loan four times a month instead of monthly. Solve for the adjusted interest rate.
(Being a smart) Is question 1, question 2 is (Lastly, you decide)
Did you write that function?
No the function came like that in the assignment.
Heres the practice problem from the lesson that was most similar to the assignment.
This is Algebra II ._. But from my understanding, 10,000 = 39,145(1 +\(\ \dfrac{0.03}{n}\))\(^{nt}\) I'm not familiar with Logarithm yet. So I don't know how to solve for \(\ t \) yet :/ maybe @ganeshie8 can help you
@tJe_FiZiCx99 Thanks for the assistance though, it is algebra II with a logarithm. Something about using the Power Property of logarithms didn't exactly help with the bases being unequal.
@tHe_FiZiCx99 *
Sorry, I'm taking Alg II and Geometry in a few weeks though. See you're in flvs though, have fun!
yes, just set it equal to 10,000 and solve t
@tHe_FiZiCx99 Haha thanks, I'll try to have "fun" with it xD. @ganeshie8 I was having trouble with that.
cx
\(\large 10,000 =39,145(1+\frac{.03}{12})^{12t} \)
start by dividing 39,145 both sides : \(\large \frac{10,000}{39,145} = (1+\frac{.03}{12})^{12t} \)
\(\large 0.25546= (1+\frac{.03}{12})^{12t} \)
now take log both sides
@ganeshie8 I got stuck after dividing on the first time I attempted this, I don't really understand by what you mean taking log on both sides though.
\(\large 0.25546= (1+\frac{.03}{12})^{12t} \) \(\large 0.25546= (1.0025)^{12t} \) take log both sides \(\large \log 0.25546= \log (1.0025)^{12t} \)
next use below property : \(\large \log a^b = b \log a\)
\(\large 0.25546= (1+\frac{.03}{12})^{12t} \) \(\large 0.25546= (1.0025)^{12t} \) take log both sides \(\large \log 0.25546= \log (1.0025)^{12t} \) \(\large \log 0.25546= 12t \log (1.0025) \) \(\large \frac{\log 0.25546}{12\log (1.0025) }= t \)
use ur calculator to evaluate the left hand side
@ganeshie8 Thanks a bunch! But what about the last part, #3?
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