simplify i630
IS it supposed to be \(\Huge\color{blue}{ \sf i^{630} }\)?
yes
\(\LARGE\color{blue}{ \sf i ^ {\color{red} { 4n+1 } } }\)\(\LARGE\color{blue}{ \sf =i ^ {\color{red} { 1 } } }\)\(\LARGE\color{blue}{ \sf = ~i }\) \(\LARGE\color{blue}{ \sf i ^ {\color{red} { 4n+2 } } }\)\(\LARGE\color{blue}{ \sf = i ^ {\color{red} { 2 } } }\)\(\LARGE\color{blue}{ \sf =~-1 { } }\) \(\LARGE\color{blue}{ \sf i ^ {\color{red} { 4n+3 } } }\)\(\LARGE\color{blue}{ \sf = i ^ {\color{red} { 3 } } }\)\(\LARGE\color{blue}{ \sf =-i {} }\) \(\LARGE\color{blue}{ \sf i ^ {\color{red} { 4n+4 } } }\)\(\LARGE\color{blue}{ \sf =i ^ {\color{red} { 4 } } }\)\(\LARGE\color{blue}{ \sf = 1 ^ {\color{red} { } } }\)
Which one would \(\LARGE\color{blue}{ \sf i ^ {\color{red} { ~~ 630 } } }\) fit ? lets see... \(\LARGE\color{blue}{ \sf i ^ {\color{red} { ~~ 630 } } }\)\(\LARGE\color{blue}{ \sf =i ^ {\color{red} { ~~( 628+2 ) } } }\)\(\LARGE\color{blue}{ \sf =i ^ {\color{red} { ~~ 628 } } }\)\(\LARGE\color{blue}{ \sf \times i ^ {\color{red} { 2 } } }\)\(\LARGE\color{blue}{ \sf =i ^ {\color{red} { ~~ (4 \times 157) } } }\)\(\LARGE\color{blue}{ \sf \times i ^ {\color{red} { ~~2 } } }\) \(\LARGE\color{blue}{ \sf = 1 \times i ^ {\color{red} { ~~ 2 } } }\)\(\LARGE\color{blue}{ \sf = i ^ {\color{red} { ~~ 2 } } }\)\(\LARGE\color{blue}{ \sf= ~ -1 }\)
See 4this fits the second (of the 4) formulas I wrote on the before.
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