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The complete combustion of liquid benzene is represented by the equation: C6H6(l) + 7.5O2(g) -> 6CO2(g) + 3H2O(l) using the data below, calculate, for this reaction, a. dH b. dS c. dG at 25 degrees C Substance: C6H6 O2 CO2 H2O dH (kJ/mol): 49 0 -394 -286 S (J/mol.K): 173 205 214 70
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The first 2 are similar calculations: dH = Hproducts - Hreactants dS = Sproducts - Sreactants then for the last: dG=dH-TdS
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