Question

I'm confused with this. Can someone PLEASE help?
When a ball is tossed into the air, the height in feet at time (t) in seconds is -16t^2+64t. At what time (t) will the ball reach it's highest point?

Answer 1

I really need help someone... :(

Answer 2

Set -16t^2+64t = 0 and solve for t (move each term over to the zero side)
16t^2 - 64t = 0; now factor it.
16t (t - 4) = 0
when you solve for t : 16t = 0 and t - 4 = 0, you get t = 0 & 4
those are the two times the ball leaves the ground and come back to the ground, at 0 and at 4 seconds.
It will be at its highest point halfway between 0 and 4.