Which function has the following characteristics? A vertical asymptote at x = -4 A horizontal asymptote at y = 0 A removable discontinuity at x = 1

Question

Which function has the following characteristics?  A vertical asymptote at x = -4 A horizontal asymptote at y = 0 A removable discontinuity at x = 1

anonymous · Answer

vertical asymptote at $x=-4$ means $-4$ makes the denominator 0 so one factor of the denominator should be $x+4$

anonymous · Answer

the removable discontinuity $x=1$ means top and bottom both have a factor of $x-1$

anonymous · Answer

so one simple answer could be 
$$f(x)=\frac{x-1}{(x+4)(x-1)}$$

anonymous · Answer

Oh ok sorry I'm new to this couldn't figure out how to type a reply lol

anonymous · Answer

Hang on here are the options given

anonymous · Answer

lol see if one is close to what i wrote

anonymous · Answer

Naw I don't see that one

anonymous · Answer

do you see that one if the denominator is multiplied out?

anonymous · Answer

Sorry I'm kinda slow what is with the denominator multiplied out?

anonymous · Answer

denominator would be $x^2+3x-4$ but if that is a problem you are not really ready for this one

anonymous · Answer

I realize that but I'm in an alternative school honestly they refuse to teach me how to learn this stuff I'd appreciate if you could show me step by step