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Because int(1/x^2, x = -2 .. -1) the result is 1/2?
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\[\int_{-2}^{-1}\frac{dx}{x^2}\]??
yeah, what i wrote
anti derivative is \(-\frac{1}{x}\)
plug in \(-2\) then plug in \(-1\) and subtract
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I did not
?
\[-\frac{1}{x}\bigg|_{-2}^{-1}\] is the usual notation but it means \[ f(-2)-F(-1)\]
you get \[-\frac{1}{-2}-(-\frac{1}{-1})\] sort out the minus signs and you will get it
oops wrong, i had that backwards!
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\[-\frac{1}{-1}-(-\frac{1}{-2})\]
so yeah, \(1-\frac{1}{2}=\frac{1}{2}\) is the answer
Now I could understand my friend, thank you ... you use facebook?
oh no
whatsapp, skype?
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