Calculate the number of grams of nitrogen gas required to make 1.22 L of ammonia at STP
Use the Ideal Gas Equation: PV = nRT; where 'n' is the amount of moles of ammonia, 'R' is the gas constant.
At STP, P = 1 atmosphere and T = 293 Kelvin
We wants to find how many moles of ammonia are in 1.22 L at STP, for this first step.
so how would you find ammonia? i'm sorry but i am just terrible at chemistry
We plug in the numbers we got so far.
\[(1 atm)(1.22 L) = n*(0.08206 \frac{L-atm}{mol-K})(293 K)\]
R is a gas constant, so it never changes. Solve for 'n', that'll be the amount of moles of ammonia.
ok
can you cross out K because when you solve for "n", you can divide potassium by itself and they cancel out. would that be correct?
Err, that K means Kelvin. And yes, all the units should be crossed out, except 'moles'.
oh wait... not potassium, it would be the Kelvins
(1atm)(I.22L)= n(24.04358L-atm/mol) is what i have so far.
Ok, now solve for n. It took you like 10 minutes to multiply?
no the atm and the mol was confusing me so i just started over and checked what i had already to make sure i was doing it right
The Liters and atmospheres units cancelled out when you divide.
so n= .o507411mols?
Not sure, lol. didn't do the math, hold on.
lol ok
Yes, so we have 0.0507 moles of ammonia, NH3. Can you use stoichiometry to figure out how many moles of Nitrogen, N, are in the ammonia?
i think so
Ok, we have 0.0507 moles of NH3. How many moles of N are there in it?
wouldn't there be 28g of moles in nitrogen?
Err, what? The molar mass of Nitrogen is 14 grams per mol.
We're not there yet. Did you find how many moles of nitrogen there are?
how did you get 14?
It's from the periodic table lol.
oh hehe lol
An atom of nitrogen weights 14 Daltons, a mole of nitrogen measures 14 grams.
in NH3, there is only one atom of nitrogen so would that make the mole of nitrogen in NH3 only 14?
Ehh, no, take it back. We got 0.0507 moles of NH3. For every mole of NH3, there is 1 mole of N, nitrogen. We get that from the molecular formula. So... \[(0.0507 mol NH_3)(\frac{1 mol N}{1 mol NH_3}) = 0.0507 mol N\]
Now, we have 0.0507 moles of N. We can now use the molar mass of N to figure out the mass.
alright so we just solve for N?
No, sorry lol. N means nitrogen.
I was trying to label both NH3 and N.
We multiply the 0.0507 moles of N by the molar mass to get the grams of nitrogen.
0.7098 grams of nitrogen
Correct.
awesome! thx!! so is that the answer?
i gtg but thx for helping me so much.
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