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OpenStudy (anonymous):
depends largely on the equation
OpenStudy (anonymous):
\[\sqrt{2x+7}=\sqrt{5x-8}\]
OpenStudy (anonymous):
square both sides and start with
\[2x+7=5x-8\] then solve for \(x\) in 3 steps
OpenStudy (anonymous):
you good from there?
OpenStudy (anonymous):
no got the first thing but got lost from there
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OpenStudy (anonymous):
you want to arrange is so all the stuff with \(x\) is on one side of the equal sign, everything else on the other
start by subtracting \(2x\) from both sides and let me know what you get
OpenStudy (anonymous):
ok so I did \[7=5x-2x-8\]
\[7=3x-8\]
\[-8 -8\]\[=15=3x\] but then I got lost
OpenStudy (anonymous):
divide by 3
OpenStudy (anonymous):
do you divide 3 form each sides?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so 3=x
OpenStudy (anonymous):
lol yeah, you "divide both sides BY 3" and yes, that is it, you are done
OpenStudy (anonymous):
oh no
what is \(15\div 3\) ?
OpenStudy (anonymous):
oh 5
OpenStudy (anonymous):
that is the one
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OpenStudy (anonymous):
ok so there is only one solution?
OpenStudy (anonymous):
yes there is only one
how many did you want?
OpenStudy (anonymous):
one I think
OpenStudy (anonymous):
good
OpenStudy (anonymous):
thx
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