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Mathematics 17 Online
OpenStudy (anonymous):

how do you solve an equation with square roots

OpenStudy (anonymous):

depends largely on the equation

OpenStudy (anonymous):

\[\sqrt{2x+7}=\sqrt{5x-8}\]

OpenStudy (anonymous):

square both sides and start with \[2x+7=5x-8\] then solve for \(x\) in 3 steps

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

no got the first thing but got lost from there

OpenStudy (anonymous):

you want to arrange is so all the stuff with \(x\) is on one side of the equal sign, everything else on the other start by subtracting \(2x\) from both sides and let me know what you get

OpenStudy (anonymous):

ok so I did \[7=5x-2x-8\] \[7=3x-8\] \[-8 -8\]\[=15=3x\] but then I got lost

OpenStudy (anonymous):

divide by 3

OpenStudy (anonymous):

do you divide 3 form each sides?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so 3=x

OpenStudy (anonymous):

lol yeah, you "divide both sides BY 3" and yes, that is it, you are done

OpenStudy (anonymous):

oh no what is \(15\div 3\) ?

OpenStudy (anonymous):

oh 5

OpenStudy (anonymous):

that is the one

OpenStudy (anonymous):

ok so there is only one solution?

OpenStudy (anonymous):

yes there is only one how many did you want?

OpenStudy (anonymous):

one I think

OpenStudy (anonymous):

good

OpenStudy (anonymous):

thx

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

yeah

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