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Physics 11 Online
OpenStudy (nottim):

A 480kg cannon fires a 10kg cannonball with a speed of 200m/s relative to the muzzle. The cannon is on wheels that roll without friction. When the cannon fires, what is the speed of the cannonball relative to the earth?

OpenStudy (nottim):

So I got -9600m/s, which doesn't seem close.

OpenStudy (nincompoop):

what is relative to the earth? you want to do a ratio of the earth's velocity revolving the sun?

OpenStudy (nottim):

I think its the cannon relative to the earth, yes?

OpenStudy (nincompoop):

what is the earth's velocity?

OpenStudy (nottim):

I'm assuming 0?

OpenStudy (anonymous):

abcd is a parallelogram in which angle adc=75 degree and side ab is produced to point e

OpenStudy (nottim):

Wrong area to post man.

OpenStudy (nottim):

Both in terms of question and section.

OpenStudy (unklerhaukus):

i think its just conservation of momentum \[\large m_\text{cannon}v_\text{cannon}=m_\text{ball}v_\text{ball}\] the speed of the ball relative to the ground is \(v_\text{ball}-v_\text{cannon}\)

OpenStudy (nottim):

\[v _{\bf}=(480kg)(200m/s)/10\] That's what I did, but it is incorrect.

OpenStudy (nottim):

v=9600 m/s

OpenStudy (unklerhaukus):

i think you've mixed up the masses

OpenStudy (nottim):

Would 4.16 make sense? Its still not like the textbook.

OpenStudy (nottim):

The textbook doesn't have the exact same question, but it is similar, and the answer was 196 m/s there.

OpenStudy (unklerhaukus):

yeah the velocity of tha cannon (relative to centre of mass) is \(v_\text{cannon}=4.167[\text{m/s}] \) the velocity of the ball relative to the earth is 200 [m/s] - v_cannon

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