A 480kg cannon fires a 10kg cannonball with a speed of 200m/s relative to the muzzle. The cannon is on wheels that roll without friction. When the cannon fires, what is the speed of the cannonball relative to the earth?
So I got -9600m/s, which doesn't seem close.
what is relative to the earth? you want to do a ratio of the earth's velocity revolving the sun?
I think its the cannon relative to the earth, yes?
what is the earth's velocity?
I'm assuming 0?
abcd is a parallelogram in which angle adc=75 degree and side ab is produced to point e
Wrong area to post man.
Both in terms of question and section.
i think its just conservation of momentum \[\large m_\text{cannon}v_\text{cannon}=m_\text{ball}v_\text{ball}\] the speed of the ball relative to the ground is \(v_\text{ball}-v_\text{cannon}\)
\[v _{\bf}=(480kg)(200m/s)/10\] That's what I did, but it is incorrect.
v=9600 m/s
i think you've mixed up the masses
Would 4.16 make sense? Its still not like the textbook.
The textbook doesn't have the exact same question, but it is similar, and the answer was 196 m/s there.
yeah the velocity of tha cannon (relative to centre of mass) is \(v_\text{cannon}=4.167[\text{m/s}] \) the velocity of the ball relative to the earth is 200 [m/s] - v_cannon
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