x-8/x+6<0
\[\frac{x - 8}{x + 6} < 0\]
wait so this is not right (x+8)=0 x=-8 (x+6)=0 x=-6 x={-8,-6}
these are the answer choises
@Hero was I wrong?
well, i think you just switch them
I'm about to perform a bit of magic
please do im so confused
big test tomorrow and im cramming
WAit I don't understand was my work wrong or right?
i attached the answer choises with the problem, and your answer was not part of the choices
dang leave it to Hero
yeah thanks for the help tho
\[\frac{x + 6 - 14}{x + 6} < 0\] \[\frac{x + 6}{x + 6} - \frac{14}{x + 6} < 0\] \[1 - \frac{14}{x + 6} < 0\] \[1 < \frac{14}{x + 6}\] \[x + 6 < 14\] \[x < 14 - 6\] \[x < 8\]
Unfortunately, that only gives us part of the answer. Intuitively you should know that -6 is a critical point.
oh ok i see what you did, than from their i would just start canceling the other answer choices.
process of elimination
thank you vary much hero.
You already circled the correct answer it seems. -6 < x < 8 or (-6,8)
I have a working theory for a modified result. I get to a point where x + 6 < 14 Then I assume 0 < x + 6 < 14 then subtract 6 from each side -6 < x < 8
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