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Integrate (x^2-4)/x * dx
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Write \[ \frac{x^2+4}x=x+\frac 4 x \] It is easy now to integrate
The integral is \[ \frac{x^2}2 +4 \ln|x| +C \]
Change the + 4ln|x| to - 4ln|x| I misread the problem.
\[ \int \frac{x^2-4}x dx\int x -4 \frac{1}x dx=\frac {x^2}2 - 4\ln|x| + C \]
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