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Mathematics 20 Online
OpenStudy (dls):

Integration question

OpenStudy (dls):

OpenStudy (dls):

@ganeshie8 @yrelhan4

OpenStudy (dls):

@mathstudent55

Miracrown (miracrown):

to clarify you want to take this integral and the [] indicate the the value is greater than the actual value?

OpenStudy (dls):

hmm..greatest integer of [2.5] means 2..floor function

ganeshie8 (ganeshie8):

divide [x^2] top and bottom

ganeshie8 (ganeshie8):

nvm, it wont help..

OpenStudy (dls):

\[\Large \int\limits_{4}^{10} \frac{dx}{1-\frac{28}{[x]}+\frac{16}{[x]^2} +1}\]

OpenStudy (dls):

:/

OpenStudy (dls):

that quadratic equation x^2-28x+196 will be = 0 when x=14 but that is out of our limits so I guess it wont be discontinuous in given integral limits ever so we won't have to worry about it maybe.

OpenStudy (anonymous):

I think the way could be splitting the integration interval in parts for which the \([x^2]\) keeps constant. You see what I mean?

OpenStudy (dls):

yep that is the only way so it will split into 6 integrals?

OpenStudy (anonymous):

I would say way more

OpenStudy (dls):

:O how more than that?

Miracrown (miracrown):

it's so complicated that im thinking there must be some trick to these!

OpenStudy (anonymous):

yes, probably

OpenStudy (dls):

I guess the longer way would be something like this: \[\Large \int\limits_4^{5} \frac{16dx}{100+16}+ \int\limits_5^6 \frac{25dx}{81+25}+\int\limits_6^7+\int\limits_7^8+\int\limits_8^9+\int\limits_9^{10}\]

Miracrown (miracrown):

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