that quadratic equation x^2-28x+196 will be = 0 when x=14 but that is out of our limits so I guess it wont be discontinuous in given integral limits ever so we won't have to worry about it maybe.
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OpenStudy (anonymous):
I think the way could be splitting the integration interval in parts for which the \([x^2]\) keeps constant. You see what I mean?
OpenStudy (dls):
yep that is the only way so it will split into 6 integrals?
OpenStudy (anonymous):
I would say way more
OpenStudy (dls):
:O how more than that?
Miracrown (miracrown):
it's so complicated that im thinking there must be some trick to these!
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OpenStudy (anonymous):
yes, probably
OpenStudy (dls):
I guess the longer way would be something like this:
\[\Large \int\limits_4^{5} \frac{16dx}{100+16}+ \int\limits_5^6 \frac{25dx}{81+25}+\int\limits_6^7+\int\limits_7^8+\int\limits_8^9+\int\limits_9^{10}\]