Question

8^k=(1/16)^2k+3

Answer 1

is it \[8^k=\left( \frac{ 1 }{16 } \right)^{2k+3}\]

Answer 2

\[\left( \frac{ 1 }{16 } \right)^{2k+3}=\left( \frac{ 1 }{2^4 } \right)^{2k+3}=\left( 2^{-4} \right)^{2k+3}=2^{-4(2k+3)}=2^{-8k-12}\]

Answer 3

\[8^k=\left( 2^3 \right)^k=2^{3k}\]
now you can solve.