Question

find the derivative of (secx+cscx)/cscx
Need step by step I get lost some where just don't know where

Answer 1

I would suggest that you start by re-writing the expression, using trig identities:

\[\frac{ \sec(x)+\csc(x) }{\csc(x) }=\frac{ \sec(x) }{\csc(x) }+\frac{ \csc(x) }{\csc(x) }=\tan(x)+1\]
Do you see why this is so?

Then you just need a couple of simple derivative rules. You probably have a list of them somewhere, but you can check here if not:
http://www.mathsisfun.com/calculus/derivatives-rules.html

Answer 2

Sorry but the correct answer is sec^2x

Answer 3

nevermind I see what you are telling me

Answer 4

Yes, that's what I got too. :)

Answer 5

Thank You!!!! A lot easier to do it that way!!!! didn't see it!