What is the equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6?

Question

luigi0210 · Answer

Perpendicular means the slope is $-\frac{1}{m}$. SO put the equation in slope intercept-form first. Then use the point-slope formula to get the equation $y-y_{1}=m(x-x_{1})$

anonymous · Answer

y=mx=b

luigi0210 · Answer

Yes, turn $2x-3y=6$ into $y=mx+b$

anonymous · Answer

y=-2/3x+2/3

luigi0210 · Answer

Actually it's just $ y=-\frac{2}{3}x-2$ but the constant doesn't really matter at this moment, just the slope. So take that slope and find the negative reciprocal of it.

anonymous · Answer

3/2

luigi0210 · Answer

Correct! Now, we have the slope $m=\frac{3}{2}$ and the point ($-2, -3)$. Use the point-slope formula to find the new equation.

anonymous · Answer

y=3/2x

luigi0210 · Answer

Let's see.. 
$$\LARGE y+3=\frac{3}{2}(x+2)$$

$$\LARGE y+3=\frac{3}{2}x+3$$
Yup, right!

anonymous · Answer

thax i got another

anonymous · Answer

Write the equation of the line that passes through (–4, 3) and is perpendicular to the line 2003-10-05-00-00_files/i0220000.jpg.

luigi0210 · Answer

Could you try the attachment again?

anonymous · Answer

attachment

luigi0210 · Answer

Could you type it? It's not showing :l

anonymous · Answer

y=7/5x-3/5

luigi0210 · Answer

Same thing, take the slope and get the negative rec. and use point slope.