Question

find attached photo… HELP

Answer 1

\(\bf \cfrac{2}{x-2}+\cfrac{1}{x+1}=\cfrac{3}{x^2-x-2}\qquad multiply\ all\ by \qquad (x-2)(x-1)
\\ \quad \\
\cfrac{2}{x-2}+\cfrac{1}{x+1}=\cfrac{3}{x^2-x-2}\implies
\\ \quad \\
{\color{red}{ \times (x-2)(x-1)}}
\\ \quad \\
\cancel{(x-2)}(x-1)\times \cfrac{2}{\cancel{x-2}}+
(x-2)\cancel{(x-1)}\times \cfrac{1}{\cancel{x+1}}\\ \quad \\=
\cancel{(x-2)(x-1)}\times \cfrac{3}{\cancel{(x-2)(x-1)}}\)

Answer 2

hmmm ahe shold be x+1 rather... lemme fix that

Answer 3

\(\bf \bf \cfrac{2}{x-2}+\cfrac{1}{x+1}=\cfrac{3}{x^2-x-2}\qquad multiply\ all\ by \qquad (x-2)(x+1)
\\ \quad \\
\cfrac{2}{x-2}+\cfrac{1}{x+1}=\cfrac{3}{x^2-x-2}\implies
\\ \quad \\
{\color{red}{ \times (x-2)(x+1)}}
\\ \quad \\
\cancel{(x-2)}(x+1)\times \cfrac{2}{\cancel{x-2}}+
(x-2)\cancel{(x+1)}\times \cfrac{1}{\cancel{x+1}}\\ \quad \\=
\cancel{(x-2)(x+1)}\times \cfrac{3}{\cancel{(x-2)(x+1)}}\)

Answer 4

then simplify and solve for "x"