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Mathematics 8 Online
OpenStudy (anonymous):

I don't understand why this is the answer (sigma notation) MEDALS

OpenStudy (anonymous):

OpenStudy (anonymous):

first to get it right gets to mate with me!

OpenStudy (anonymous):

That's embarrassing. Ma'am, we're here to ask or answer questions. Not sell ourselves online. Please get your act together.

OpenStudy (rock_mit182):

the only thing i know is the girl in the pictuare is hot! LOL

OpenStudy (anonymous):

;)

OpenStudy (anonymous):

Studied this problem a little, found something interesting. Basically this notation is saying: "Add up the first 'n' terms in the sequence (9k+5), while k=1." The confusing bit is that I don't know what 'n' terms represents. I plugged in pi instead of 'n' to see what the result would be. I got 74.74. Then I took that answer, went back to the answer of the problem you presented, and substituted pi in for n. (1/2)pi(9pi + 19) turned out to be 74.30! That's just shy of 74.74...Would N = Pi? This is a very interesting problem. I'm going to look into it a little more, see what I can find.

OpenStudy (anonymous):

Also, I hope I didn't offend you in any way. That's not my intent. But ma'am, we must take care. There are children on this site too; we must set an example.

OpenStudy (anonymous):

hey thanks for the help dude. no offense taken, im a dude

OpenStudy (anonymous):

pi? lol the answer is right

OpenStudy (anonymous):

i know the answer is right, i just want an explanation for it

OpenStudy (anonymous):

please

OpenStudy (anonymous):

A dude, huh? It's always good to be enlightened. Hey, I'm working through this thing right now. I'll get back to you when I see the light! :D

OpenStudy (anonymous):

ooh i see sorry, i thought you wanted to see why it was wrong there are two ways to solve this

OpenStudy (anonymous):

ok whats the fastest

OpenStudy (anonymous):

this way the first term is what you get when you replace \(k\) by \(1\) namely \(9\times 1+5=14\) the last term is what you get when you replace \(k\) by \(n\) i.e. \(9n+5\) add them together and get \(9n+5+14=9n+19\) multiply by \(n\) then divide by \(2\) and get \[\frac{1}{2}n(9n+19)\]

OpenStudy (anonymous):

one half times the first term plus the last term times the number of terms is the "formula"

OpenStudy (anonymous):

nice, you're a winner. thanks pal

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

That's beautiful. Thanks S73! You made my day.

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