Question

@NickDantzlerward

Answer 1

The function f(x) = (1.008735)12x models the monthly interest that a bank offers to Dan after x years. Dan converts the function to have x isolated in the exponent. What is the approximate rate of growth?

11%

12%

13%

14%

Answer 2

i think its 12%

Answer 3

please help @allay

Answer 4

urgent

Answer 5

Wow, this is interesting. How did you try and solve?

Answer 6

i just did (1.008735)12 and got 12.1 is it right

Answer 7

I have a feeling we can't jump to that conclusion quickly. They want us to modify the function in such a way that x is part of the exponent. How to do that, though...

Answer 8

its fine, what about this one

Answer 9

Which exponential function goes through the points (1, 8) and (4, 64)?

f(x) = 4(2)x

f(x) = 2(4)x

f(x) = 4(2)-x

f(x) = 2(4)-x

Answer 10

@helpme1.2 @johnweldon1993

Answer 11

This is awesome. Tell you what, give me a little bit to think both of your problems through. You'll probably get the answers by the time I come back to you; but I will find out how these work. These are pretty good.

Answer 12

I'll just save this link for quick access...

Answer 13

Hang tough, keep thinking. I'll be doing it too. I really want to learn how to do these efficiently. :D

Answer 14

Got it.

Your first question has the answer of (A). Ask yourself this question: "I need a function that when I put in a value for x, I get a very certain value of y." In this case, you need a function such that when the specific input value of 'x' - or 1 - is plugged in, you get the certain output 'y' value of 8. You also need a function such that when the specific input value of 'x' - or 4 - is plugged in, you get the certain output 'y' value of 64.

Look at A. ( f(x) = 4(2)^x ) When x = 1, then 4(2)^1 = 8! We got a return value of 8, which is 'y'. This is a good thing! Let's try this when x = 4. We should get a 'y' return value of 64.

When x = 4, then 4(2)^4 = 4(16) = 64, which is our needed 'y' output! The answer, then, is A.

The second question doesn't make any sense. The graph is not a line, and because it changes exponentially, you can't approximate any values. Things keep moving. You can't solve this question.

Hope I helped. Awesome stuff, BTW.