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Mathematics 14 Online
OpenStudy (anonymous):

Topic: Base e and Natural logs ln 8x=3 plzzz need help with this and a good explanation

OpenStudy (jdoe0001):

\(\bf ln(8x)=3 \implies log_e(8x)=3 \\ \quad \\ \textit{using the log cancellation rule of }\Large {\color{blue}{ a}}^{log_{\color{blue}{ a}}(x)}=x\qquad thus \\ \quad \\ log_e(8x)=3\implies {\Large {\color{blue}{ e}}^{log_{\color{blue}{ e}}(8x)}={\color{blue}{ e}}^3 }\implies 8x=e^3\)

OpenStudy (jdoe0001):

and you can take it from there

OpenStudy (anonymous):

lol well that's the part I get stuck on idk what to do at that point

OpenStudy (anonymous):

2^3 is 8

OpenStudy (jdoe0001):

well, just divide both sides by 8, like on any linear simplification

OpenStudy (anonymous):

so 3^3/8x

OpenStudy (anonymous):

8

OpenStudy (anonymous):

.1373

OpenStudy (jdoe0001):

3^3?

OpenStudy (anonymous):

I mean e^3

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