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Topic: Base e and Natural logs ln 8x=3 plzzz need help with this and a good explanation
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\(\bf ln(8x)=3 \implies log_e(8x)=3 \\ \quad \\ \textit{using the log cancellation rule of }\Large {\color{blue}{ a}}^{log_{\color{blue}{ a}}(x)}=x\qquad thus \\ \quad \\ log_e(8x)=3\implies {\Large {\color{blue}{ e}}^{log_{\color{blue}{ e}}(8x)}={\color{blue}{ e}}^3 }\implies 8x=e^3\)
and you can take it from there
lol well that's the part I get stuck on idk what to do at that point
2^3 is 8
well, just divide both sides by 8, like on any linear simplification
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so 3^3/8x
8
.1373
3^3?
I mean e^3
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