Help pls? c': Divide. (6a^4 + 2a^3) ÷ 2a @bibby ?
You can rewrite the fraction as \[\huge \frac{ 6a^4}{ 2a } +\frac{ 2a^3}{ 2a } \]
that's some interesting math you're working there Start with the left hand side. What is a^4/a You can rewrite it:\[\huge \frac{ a^4 }{ a }=\frac{ a*a*a*a }{ a }\]
Yeah. You can't add things with different exponents. it might help if you think of them as shapes or fruits. if a^4's are apples and a^3's are oranges You can only add apples+apples. oranges+oranges. not oranges + apples
anyhow \[\huge \frac{ a^4 }{ a }=\frac{ \cancel a*a*a*a }{ \cancel a }\]
Okay, so now a^3? @bibby
that's not everything. We have the following: \[\huge \frac{ 6a^4}{ 2a } +\frac{ 2a^3}{ 2a }= \frac{ 6a^3}{ 2 } +\frac{ 2a^3}{ 2a }\] Let's finish the left side. What is 6/2?
3 @bibby
:3 So\[\huge 3a^3 +\frac{ 2a^3}{ 2a }\] What can we do with the right side?
divide? but could you put a 1 under 3a^3?
Do you want to add the two terms? You can't do that yet as they don't have common denominators.
I'm not sure @bibby
OK take \[\huge\frac{ 2a^3}{ 2a }\]alone try simplifying that
4a^4?
wait
waiting
1a^3???
divide? I don't even know
yeah. you got it right. a^3
I'll write it out\[\huge\frac{ 2a^3}{ 2a }=\huge\frac{ \cancel 2a^{\cancel32}}{ \cancel2\cancel a }\]
actually you got it wrong, whoops
^2?
a^2 ***
Yeah. Recall the exponent division rule from earlier. a^3/a= a^(3-1) = a^2
\[\huge 3a^3 +{ a^2}\]and we're done
You can factor out a^2 though: a^2(3a + 1)
Ohhhh. Okay, I wasn't getting the exponent division rule. Thank you!
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