Question

Solve the system using elimination how to find y? I found ex 3 but not y
3x-2y=1
2x+2y=14

Answer 1

if \(x=3\) then since \(3x-2y=1\) you know
\[3\times 3-2y=1\] or
\[9-2y=1\] and you can solve that for \(y\)

Answer 2

alternatively, solve
\[2\times 3+2y=14\] or
\[6+2y=14\] you will get the same answer

Answer 3

I'm a little confused here could you explain from the beginning

Answer 4

did you find \(x=3\) ?

Answer 5

no how did you get that?

Answer 6

i thought you said \(x=3\) up top

Answer 7

oh yeah I found that

Answer 8

ok then the simplest way i know how to say it is that if x is 3 then you can replace x by 3 in either of the two original equation

Answer 9

that is why i wrote \[2\times 3+2y=14\] or \[2\times 3+2y=14\]

Answer 10

I know the answer is 4 just not sure how i got it

Answer 11

do you know how to solve \[6+2y=14\]?"

Answer 12

you divide 6 by 6 and 6 by 2 or?

Answer 13

subtract 6
then divide by 2

Answer 14

okay I got it now thank you :)

Answer 15

yw