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OpenStudy (anonymous):
@mathslover
mathslover (mathslover):
Well, in order to simplify this, we can first take the whole fraction in a single bracket :
\((\cfrac{\sf{n+1}}{\sf{n}})^n\)
mathslover (mathslover):
Is it okay to you?
OpenStudy (anonymous):
What's next?
mathslover (mathslover):
\((\cfrac{n}{n} + \cfrac{1}{n})^n\) .. Can you simplify it further?
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OpenStudy (anonymous):
So it's (1+1/n)^n?
mathslover (mathslover):
We can simplify it very easily further too
mathslover (mathslover):
But, in that case , :
i) We'll use Binomial Theorem
ii) n should be greater than 1
mathslover (mathslover):
You can take it like this :
CASE - 1 : If n > 1
\((1+\cfrac{1}{n})^n = 1 + (\cfrac{1}{n} \times n) \\
= 1 +( \cfrac{1}{\cancel{n}^1} \times \cancel{n}^1) \\
= 1+ 1 = 2 \)
mathslover (mathslover):
It is a theorem actually :
(1+x)^n = 1 + nx
if x is lesser than 1
here, 1/n will be lesser than 1 only if n > 1 so, if n>1 , (1+1/n)^n = 2
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