sfgmfgmgh
is there a drawing that goes with this? If the rider's speed is 11m/s when he reaches D, then you only need to consider the formula for kinetic energy:\[KE=\frac{ 1 }{ 2 } mv ^{2}\]where KE is the kinetic energy; m is mass; and v is the velocity (speed in this case).
so i just fill in the blank and I have my answer?
Assuming there's no other information, you only know mass and velocity. Have you learned any other expressions for kinetic energy?
The equation will lead you right to it. The kinetic energy is one half times the mass time the velocity (or speed in this case) squared. The problem gives you the mass and the speed.
\[KE =\frac{ 1 }{ 2 } (100 kg)(11 m/s)\]
like this?
@PsiSquared
my answer 6050 kg * m^2/s^2 = 6050?
Yes, but you need units. It happens that:\[6050 \frac{ kg∙m ^{2} }{ s ^{2} }=6050 joules=6050J\]Joules are a unit of energy.
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