Question

In how many ways could you choose two different letters from the letters C, O, U, N, T?
A. 60 ways
B. 20 ways
C. 120 ways
D. 10 ways

Answer 1

pretty sure it would be \[P_{5}^{2}\] so your equation would be \[\frac{ 5! }{ (5-2)! }\] meaning your answer would be 20

Answer 2

Thank you! I have been trying to figure that out for the last 20mins. I knew it was P something

Answer 3

there are 5 letters in total
so out of 5 we choose anyone 4 the first place
and now 4 2nd place there r 4 remaining so 4ways
so total ways = 4*5=20

Answer 4

i would say its
\[\left(\begin{matrix}5 \\ 2\end{matrix}\right)\] = 10 ways
since order doesnt matter right?

Answer 5

we need 2 different letters

Answer 6

Well, I did the 4 * 5 and I got 20, so Ima put it down and see.

Answer 7

https://answers.yahoo.com/question/index?qid=20100520132011AAzJwcR
this will help

Answer 8

go for it @xDemonicWolfiex
@jayz657 did u understand?

Answer 9

Maybe it is 10.
I dont want to miss this question. I know it, but I can't decide between 10 or 20

Answer 10

i think you double counted since the order does not matter you get a double count
ex: CO is the same as OC order doesnt matter so you dont count both

Answer 11

@Mashy

Answer 12

yea it should be 10 ways!

Answer 13

yea was 90% sure since i am taking probability right now lol