I know the answer is 4 but can someone show me how that was found? A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equal probability of winning. If the winner is to be drawn using 10 balls numbered 0 through 9, how many balls need to be picked, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers?
It sounds like we choose n balls out of 10 (and we don't know n) there 10 Choose n combinations we want this to be 210 or bigger, so each person gets a unique combination \[\left(\begin{matrix}10 \\ n\end{matrix}\right)≥210\]
off-hand, I don't know how to "solve" for n other than trying some numbers and see what is the smallest n the works.
Im so confused. I just found out the answer isn't 4 it is either 5 or 6. But I can't fiqure out how those numbers make sense.
The question is not very clear. What they are doing is a bit mysterious... one of those goofy questions where only the asker (maybe) has an idea of what they want.
lol watch when I fiquired it out it will be something so simple. Or maybe not. :P
If you find out, please post the answer and explanation here. It helps me understand "goofy questions". Good luck.
thanks I will
thanks
Join our real-time social learning platform and learn together with your friends!