Question

How do i solve 3x^2+2x+7=0 ?
Will give medal to whoever helps
Please be patient with me kind of tired so my brain is not working well right now

Answer 1

So we divide both sides by 7?

Answer 2

Ohh okay thanks

Answer 3

I hate these problems >.< but i'm good at them. It's stupid. Lol
let me start over I lost my trin of thought, I know a better way, sorry /)_-

Answer 4

Lol okay (:

Answer 5

Reorder the terms:
7 + 2x + 3x2 = 0
Divide all terms by, 3 the coefficient of the squared term:
Divide each side by '3'.
2.333333333 + 0.6666666667x + x2 = 0
Move the constant term to the right:
Add '-2.333333333' to each side of the equation.
2.333333333 + 0.6666666667x + -2.333333333 + x2 = 0 + -2.333333333
Reorder the terms:
2.333333333 + -2.333333333 + 0.6666666667x + x2 = 0 + -2.333333333
Combine like terms: 2.333333333 + -2.333333333 = 0.000000000
0.000000000 + 0.6666666667x + x2 = 0 + -2.333333333
0.6666666667x + x2 = 0 + -2.333333333
Combine like terms: 0 + -2.333333333 = -2.333333333
0.6666666667x + x2 = -2.333333333
The x term is 0.6666666667x. Take half its coefficient (0.3333333334).
Square it (0.1111111112) and add it to both sides.
Add '0.1111111112' to each side of the equation.
0.6666666667x + 0.1111111112 + x2 = -2.333333333 + 0.1111111112
Reorder the terms:
0.1111111112 + 0.6666666667x + x2 = -2.333333333 + 0.1111111112
Combine like terms: -2.333333333 + 0.1111111112 = -2.2222222218
0.1111111112 + 0.6666666667x + x2 = -2.2222222218
Factor a perfect square on the left side:
(x + 0.3333333334)(x + 0.3333333334) = -2.2222222218

Answer 6

I don't like fractions... decimals are better to use. But 0.66667 = 2/3

Answer 7

I gtg, sorry :/ I'd explain it but I have to go do my chores D:

Answer 8

its okay thank you! (: bye

Answer 9

I hope this even helped. This is how my teacher taught me to do these. She's kind of annoying.

Answer 10

It did and lol yeah my math teacher is really annoying and she doesnt explain well :P

Answer 11

Ok, What You Have There, The Equation, Is In Standard Form
ax^2+bx+c=0
\[3x^2+2x+7=0\]
Do You See The Similarity? ☺

Answer 12

yes

Answer 13

Ok, Good. Now What You Want To Do With That Equation Is Plug It Into "The Quadratic Formula", Which Is...
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Do You Know What To Do Next?

Answer 14

not really i learned this but i didnt understand it well.

Answer 15

Ok Well See Look At This Equation Closely,
\[3x^2+2x+7=0\]
\[ax^2+bx+c=0\]
Where
3=a
2=b
7=c
Now All You Have To Do Is Plug In Those Numbers Into The Quadratic Formula.
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Do You Know What I Mean? :o

Answer 16

yes that part I get, what I mean is how to solve it.

Answer 17

Ok That Is Totally Fine.
\[x=\frac{ -2\pm \sqrt{2^2-4\times3\times7} }{ 2\times3 }\]
\[x=\frac{ -2\pm \sqrt{4-4\times3\times7} }{ 6 }\]
\[x=\frac{ -2\pm \sqrt{4-84} }{ 6 }\]
\[x=\frac{ -2\pm \sqrt{-80} }{ 6 }\]

Answer 18

Are You Getting What To Do Now...?

Answer 19

um i guess what is the + with the underline?

Answer 20

Oh Ok, Well That Means Plus Or Minus. Which Means There Are Going To Be 2 Answers. First You Solve That Equation By Adding, Then Once You Get The Answer, You Do It Again But This Time You Subtract Instead.

Answer 21

does the 80 stay a negative? cause im trying to find the square root of it and it keeps saying invalid input