A ball is dropped from a bridge at a height of 176.4 over a river. After 2s, a second ball is thrown straight downwards. What should be the initial velocity of the second ball so that both hit the water simultaneously?
The given answer is 24.5 m/s. Help appreciated.

Question

A ball is dropped from a bridge at a height of 176.4 over a river. After 2s, a second ball is thrown straight downwards. What should be the initial velocity of the second ball so that both hit the water simultaneously?
The given answer is 24.5 m/s. Help appreciated.

anonymous · Answer

Ball 1: Initial velocity is zero. Find the time it takes it to fall 176.4 m.
Ball 2: Time = time for ball 1 to fall + 2s.
Solve for initial velocity of ball 2. For both balls, use:$$\vec{d} = \vec{v}\cdot t + \dfrac{1}{2}\vec{g}t^2$$

anonymous · Answer

Formula didn't show up properly. It should be: $$\textbf{d}= \textbf{v}t + \dfrac{1}{2}\textbf{g}t^2$$