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Mathematics 21 Online
OpenStudy (anonymous):

just one question real quick?!

OpenStudy (anonymous):

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

O.O

OpenStudy (anonymous):

Just guess :DD

OpenStudy (anonymous):

nah.

OpenStudy (amistre64):

factor ... then cancel

OpenStudy (amistre64):

a shortcut may be let x=1, or x=0 and see what everything will produce

OpenStudy (anonymous):

okay. ill see what that gets me.

OpenStudy (anonymous):

wait was the one i chose correct?!

OpenStudy (anonymous):

\[\frac{ \frac{ 12x-96 }{ x^2-4x-32 } }{ \frac{ 6x^2-6x-12 }{3x+3 } }\] \[=\frac{ 12(x-8) }{x^2-8x+4x-32 }\times \frac{ 3\left( x+1 \right) }{6\left( x^2-2x+x-2 \right) }\] \[=\frac{ 6\left( x-8 \right) }{x \left( x-8 \right)+4\left( x-8 \right) }\times \frac{ x+1 } { x(x-2)+1(x-2) }\] make factors and cancel the common.

OpenStudy (amistre64):

-96/-32 ------- -12/ 3 -8/-32 ------- -1/ 3 -8 ------- = -1/12 for x=0 32* 3

OpenStudy (anonymous):

okay thank you!

OpenStudy (amistre64):

err, -3/4 that is

OpenStudy (amistre64):

so yeah, 6/8 = 3/4 is a match

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