Question

using fundamental identities

Answer 1

one divided by cotangent of theta to the second power. + sec θ cos θ

Answer 2

Equation editor please? @_@

Answer 3

Well did you know that \(\large cos \theta=\frac{1}{sec \theta}\)

Answer 4

And \(cot^2 \theta=\frac{1}{tan^2 \theta}\)

Answer 5

\[1/\cot ^2\theta + \sec \theta \cos \theta \]

Answer 6

what is cot? its not even on my calculator

Answer 7

\[\LARGE cot\theta=\frac{1}{tan\theta} \]

Answer 8

They're reciprocals of each other..

Answer 9

Do you mean in terms of sin and cos..?

Answer 10

.-. no... i dont get the section im learning, pretend ive never heard these words before because your speaking a different language for they are nothing but confusing symbols

Answer 11

Hmm, well do you know your basic trig identities?

Answer 12

i can plug them into a calculator c: does that count?

Answer 13

Actually, when you are doing identities, you have to it by hand. Calculators are only of you have exact values to plug in.

Answer 14

*only if

Answer 15

Okay, here, I will try and help by explanation?

Answer 16

Okay, so we have \(\large \frac{1}{cot^2 \theta}+sec\theta ~ cos \theta\) right?

Answer 17

indeed

Answer 18

Now, if you know your trig identities(which is extremely helpful to have memorized) then you can change everything into sin/cos's
\[\LARGE cot^2 \theta =\frac{cos^2 \theta}{sin^2 \theta}\]
\[\LARGE sec \theta = \frac{1}{cos \theta}\]
Now plug them in:
\[\Huge \frac{1}{\frac{cos^2\theta}{sin^2\theta}}+\frac{1}{cos\theta}(cos\theta)\]
Can you simplify that?

Answer 19

no, how the crap do you have a triple fraction

Answer 20

Lui just loves you

Answer 21

By changing the \(cot^2 \theta\) into sin/cos's..
If it makes it easier..
\[\Huge \frac{1}{\frac{cos^2\theta}{sin^2\theta}}=tan^2 \theta\]
So we can have \[\Huge tan^2 \theta+\frac{1}{cos\theta}(cos\theta)\] instead.

Answer 22

@ShadowLegendX >_>

Answer 23

^my thoughts exactly
and you just wrote the same equation i started with

Answer 24

Multiply those two to get 1..
\[\LARGE tan^2 \theta +1\]

Answer 25

well yeah theyd cancel eachother out

Answer 26

And that's an identity.. so it's just \(\LARGE sec^2 \theta\) as a final answer. ._.

Answer 27

wait why wouldnt it be 1tan^2theta?

Answer 28

Reason I'm not going to consider "teaching" as a career >_<

And it could be either one. \(sec^2\theta\) is just simplified.

Answer 29

hey now, im anything but stupid, im in all ap and honors classes and i already have 1 and a half years of college done when im only in 11th grade. i just REALLY suck at math.

Answer 30

Well congrats on that, and good luck too.. sounds tough. :)

Answer 31

not really.... next year i have ap stats and ap physics... thats whats going to be tough /).(\ can you help with a few more?

Answer 32

Does you being cute have to do with your classes flying by?

Answer 33

(。・_・。) what? my classes are hard as all get out i just have to hit the books really hard to pass.

Answer 34

What else do you hit?

Answer 35

Hmm, you interest me a bit, not gonna lie(not trying anything here >_>)..
But yea, sure.. I'll help and try not to confuse you at the same time xD

Answer 36

Open a new question.

Answer 37

kk